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What is the principal value of \(\sin^{-1}\left(\sin\left(-\frac{5\pi}{6}\right)\right)\)?\(\sin^{-1}\left(\sin\left(-\frac{5\pi}{6}\right)\right)\) का मुख्य मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \(-\frac{\pi}{6}\)\(-\frac{\pi}{6}\)
Since \(\sin\left(-\frac{5\pi}{6}\right)=-\frac{1}{2}\), \(\sin^{-1}\left(-\frac{1}{2}\right)=-\frac{\pi}{6}\). The answer must lie in the principal range.\(\sin\left(-\frac{5\pi}{6}\right)=-\frac{1}{2}\), इसलिए \(\sin^{-1}\left(-\frac{1}{2}\right)=-\frac{\pi}{6}\)। उत्तर मुख्य परिसर में होना चाहिए।
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