What is the value of \(\cos^{-1}\left(\frac{\sqrt{2}}{2}\right)\)?\(\cos^{-1}\left(\frac{\sqrt{2}}{2}\right)\) का मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \(\frac{\pi}{4}\)\(\frac{\pi}{4}\)
Since \(\cos\frac{\pi}{4}=\frac{\sqrt{2}}{2}\) and \(\frac{\pi}{4}\in\left[0,\pi\right]\). Remember the table of special values.\(\cos\frac{\pi}{4}=\frac{\sqrt{2}}{2}\) और \(\frac{\pi}{4}\in\left[0,\pi\right]\)। विशेष मानों की तालिका याद रखें।
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