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What is the principal value of \(sec^{-1}\left(-2\right)\)?\(sec^{-1}\left(-2\right)\) का मुख्य मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \(\frac{2\pi}{3}\)\(\frac{2\pi}{3}\)
Since \(sec\frac{2\pi}{3}=-2\) and it lies in the principal range of \(sec^{-1}x\), the answer is \(\frac{2\pi}{3}\).\(sec\frac{2\pi}{3}=-2\) और यह \(sec^{-1}x\) के मुख्य परिसर में है। इसलिए उत्तर \(\frac{2\pi}{3}\) है।
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