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What is the value of \(cosec^{-1}2\)?

Answer and explanation

Correct answer: \(\frac{\pi}{6}\)

Since \(cosec\,\frac{\pi}{6}=\dfrac{1}{\sin(\pi/6)}=\dfrac{1}{1/2}=2\), the principal value is \(cosec^{-1}2=\frac{\pi}{6}\). The other options are incorrect because \(cosec\,\frac{\pi}{3}=\dfrac{2}{\sqrt{3}}\), \(cosec\,\frac{\pi}{4}=\sqrt{2}\) and \(cosec\,\frac{\pi}{2}=1\), none of which equals 2. Exam tip: use \(cosec\theta=1/\sin\theta\) and remember standard sine values for common angles.

Related tags

Inverse Trigonometric FunctionsStandard ValuesArccosecTrigonometryPrincipal Value BranchMathematicsClass 12 Mcq

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