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What is the principal value of \(\cot^{-1}1\)?

Answer and explanation

Correct answer: \(\frac{\pi}{4}\)

Since \(\cot(\pi/4)=1\) and the principal value of \(\cot^{-1}x\) is taken in the interval \(0<\cot^{-1}x<\pi\), we get \(\cot^{-1}1=\frac{\pi}{4}\). The closest distractor \(\frac{\pi}{2}\) is incorrect because \(\cot(\pi/2)=0\). Exam tip: remember the principal-value range of arccot is \((0,\pi)\).

Related tags

Inverse Trigonometric FunctionsArccotPrincipal ValueTrigonometryClass 12Principal Value BranchMathematicsClass 12 Mcq

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