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What is the value of \(\tan^{-1}0\)?

Answer and explanation

Correct answer: 0

Since \(\tan 0=0\), the angle whose tangent is 0 is 0, so \(\tan^{-1}0=0\). Also remember the principal value range of \(\tan^{-1}x\) is \((-\tfrac{\pi}{2},\tfrac{\pi}{2})\), so values like \(\pi\) or \(\tfrac{\pi}{2}\) are not valid principal outputs. The closest distractor \(\tfrac{\pi}{4}\) is wrong because \(\tan(\tfrac{\pi}{4})=1\), not 0. Exam tip: always use the definition \(\tan(\theta)\) and the principal range of \(\tan^{-1}\) to find inverse values quickly.

Related tags

Inverse Trigonometric FunctionsArctanPrincipal ValueTrigonometryClass12Principal Value BranchMathematicsClass 12 Mcq

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