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Find the value of \(\cos^{-1}1\).

Answer and explanation

Correct answer: \(0\)

The principal value of arccos, \(\cos^{-1}x\), lies in \([0,\pi]\). Since \(\cos0=1\) and 0 is within this principal range, \(\cos^{-1}1=0\). Closest distractors fail: \(\frac{\pi}{2}\) gives \(\cos=0\), \(\pi\) gives \(\cos=-1\), and \(-\frac{\pi}{2}\) is outside the principal range, so none are correct. Exam tip: memorize that the principal value range of arccos is \([0,\pi]\).

Related tags

Inverse Trigonometric FunctionsArccosPrincipal ValueTrigonometryPrincipal Value BranchMathematicsClass 12 Mcq

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