Update

Muft Shiksha™ एक 100% Free Education Portal है 🇮🇳, जिसका उद्देश्य Class 9–12 के हर विद्यार्थी तक High-Quality Education को पूरी तरह मुफ्त पहुँचाना है। 🇮🇳 हम मानते हैं कि अच्छी शिक्षा किसी student की आर्थिक स्थिति पर निर्भर नहीं होनी चाहिए। 🇮🇳 हर विद्यार्थी को वही Quality Study Material, MCQs, Quizzes, Exam Preparation, Concept-Based Learning और Bilingual Support मिलना चाहिए, जो आमतौर पर महंगी Coaching या Premium Platforms में मिलता है। Muft Shiksha™ 🇮🇳 इसी सोच के साथ बनाया गया है

Subjects
0 reads0 ratings0 helpful

What is the principal value range of the inverse sine function \(\sin^{-1}x\)?

Answer and explanation

Correct answer: \(\left[-\frac{\pi}{2},\frac{\pi}{2}\right]\)

The value of \(\sin^{-1}x\) always lies in \(\left[-\frac{\pi}{2},\frac{\pi}{2}\right]\), where \(\sin x\) is one-one. The interval \([0,\pi]\) is the principal value range of \(\cos^{-1}x\), not inverse sine. Exam tip: memorise the standard principal ranges of inverse trigonometric functions.

Related tags

Inverse Trigonometric FunctionsInverse SinePrincipal Value RangeClass 12 MathematicsTrigonometryIntroduction To Inverse Trigonometric FunctionsMathematicsClass 12 Mcq

Was this question useful?

No ratings yetWrite a review / Rate this question

Student Reviews

No published reviews yet.

Add Muft Shiksha to your Home Screen

In Safari, tap Share, then Add to Home Screen.