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What is the principal value of (\sec^{-1}(-\sqrt{2}))?(\sec^{-1}(-\sqrt{2})) का मुख्य मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (\frac{3\pi}{4})(\frac{3\pi}{4})
From (\sec y=-\sqrt{2}), (\cos y=-\frac{1}{\sqrt{2}}), so the principal value is (y=\frac{3\pi}{4}). For (\sec^{-1}), decide the quadrant from the sign.(\sec y=-\sqrt{2}) से (\cos y=-\frac{1}{\sqrt{2}}), इसलिए मुख्य मान (y=\frac{3\pi}{4}) है। (\sec^{-1}) में चिह्न से चतुर्थांश तय करें।
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