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If \(\tan^{-1}x=-\frac{\pi}{6}\), what is the value of (x)?यदि \(\tan^{-1}x=-\frac{\pi}{6}\), तो (x) का मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \(-\frac{1}{\sqrt{3}}\)\(-\frac{1}{\sqrt{3}}\)
From \(\tan^{-1}x=-\frac{\pi}{6}\), \(x=\tan\left(-\frac{\pi}{6}\right)=-\frac{1}{\sqrt{3}}\). The range of \(\tan^{-1}\) also includes negative angles.\(\tan^{-1}x=-\frac{\pi}{6}\) से \(x=\tan\left(-\frac{\pi}{6}\right)=-\frac{1}{\sqrt{3}}\)। \(\tan^{-1}\) का परिसर ऋणात्मक कोण भी लेता है।
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