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If (\sin^{-1}x=\frac{\pi}{4}), what is the value of (x)?यदि (\sin^{-1}x=\frac{\pi}{4}), तो (x) का मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (\frac{1}{\sqrt{2}})(\frac{1}{\sqrt{2}})
From (\sin^{-1}x=\frac{\pi}{4}), (x=\sin\frac{\pi}{4}=\frac{1}{\sqrt{2}}). Convert the inverse form into the normal trigonometric form.(\sin^{-1}x=\frac{\pi}{4}) से (x=\sin\frac{\pi}{4}=\frac{1}{\sqrt{2}})। प्रतिलोम को सामान्य त्रिकोणमितीय रूप में बदलें।
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