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What is the value of \(\cos^{-1}\left(-\frac{1}{2}\right)\) in the principal branch?मुख्य मान शाखा में \(\cos^{-1}\left(-\frac{1}{2}\right)\) का मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \(\frac{2\pi}{3}\)\(\frac{2\pi}{3}\)
The range of \(\cos^{-1}x\) is \(\left[0,\pi\right]\) and in this range \(\cos\frac{2\pi}{3}=-\frac{1}{2}\). Do not take a negative angle as principal value.\(\cos^{-1}x\) का परिसर \(\left[0,\pi\right]\) है और इस परिसर में \(\cos\frac{2\pi}{3}=-\frac{1}{2}\)। ऋणात्मक उत्तर को मुख्य मान न मानें।
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