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What is the value of \(\sin^{-1}\left(\frac{1}{2}\right)\) in the principal branch?मुख्य मान शाखा में \(\sin^{-1}\left(\frac{1}{2}\right)\) का मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \(\frac{\pi}{6}\)\(\frac{\pi}{6}\)
The range of \(\sin^{-1}x\) is \(\left[-\frac{\pi}{2},\frac{\pi}{2}\right]\) and \(\sin\frac{\pi}{6}=\frac{1}{2}\). Always remember the principal range in exams.\(\sin^{-1}x\) का परिसर \(\left[-\frac{\pi}{2},\frac{\pi}{2}\right]\) होता है और \(\sin\frac{\pi}{6}=\frac{1}{2}\)। परीक्षा में हमेशा मुख्य मान परिसर याद रखें।
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