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If (x>0), what is the value of (\tan^{-1}x+\cot^{-1}x)?यदि (x>0) हो तो (\tan^{-1}x+\cot^{-1}x) का मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (\frac{\pi}{2})(\frac{\pi}{2})
When (x>0), (\tan^{-1}x+\cot^{-1}x=\frac{\pi}{2}). Keep the principal range of (\cot^{-1}x) in mind.जब (x>0) हो तो (\tan^{-1}x+\cot^{-1}x=\frac{\pi}{2}) होता है। (\cot^{-1}x) की प्रधान सीमा का ध्यान रखें।
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