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For \(\sin^{-1}(2x)\) to be real, in which interval should (x) lie?\(\sin^{-1}(2x)\) के वास्तविक होने के लिए (x) किस अंतराल में होना चाहिए?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \(\left[-\frac{1}{2},\frac{1}{2}\right]\)\(\left[-\frac{1}{2},\frac{1}{2}\right]\)
For \(\sin^{-1}(2x)\), we need \(-1\le 2x\le1\). This gives \(x\in\left[-\frac{1}{2},\frac{1}{2}\right]\).\(\sin^{-1}(2x)\) के लिए \(-1\le 2x\le1\) होना चाहिए। इससे \(x\in\left[-\frac{1}{2},\frac{1}{2}\right]\) मिलता है।
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