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What is the value of \(\cos^{-1}\left(-\frac{1}{\sqrt{2}}\right)\)?\(\cos^{-1}\left(-\frac{1}{\sqrt{2}}\right)\) का मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \(\frac{3\pi}{4}\)\(\frac{3\pi}{4}\)
Because \(\cos\frac{3\pi}{4}=-\frac{1}{\sqrt{2}}\) and \(\frac{3\pi}{4}\in[0,\pi]\). For \(\cos^{-1}\), do not take a negative principal value.क्योंकि \(\cos\frac{3\pi}{4}=-\frac{1}{\sqrt{2}}\) और \(\frac{3\pi}{4}\in[0,\pi]\) है। \(\cos^{-1}\) में प्रधान मान ऋणात्मक नहीं लेते।
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