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What is the value of \(\sin^{-1}\left(\frac{1}{\sqrt{2}}\right)\)?\(\sin^{-1}\left(\frac{1}{\sqrt{2}}\right)\) का मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \(\frac{\pi}{4}\)\(\frac{\pi}{4}\)
Because \(\sin\frac{\pi}{4}=\frac{1}{\sqrt{2}}\). Standard angle values are very useful in exams.क्योंकि \(\sin\frac{\pi}{4}=\frac{1}{\sqrt{2}}\) है। मानक कोणों के मान परीक्षा में बहुत उपयोगी होते हैं।
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