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What is the principal value of \(\tan^{-1}\left(\frac{1}{\sqrt{3}}\right)\)?\(\tan^{-1}\left(\frac{1}{\sqrt{3}}\right)\) का प्रधान मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \(\frac{\pi}{6}\)\(\frac{\pi}{6}\)
Because \(\tan\frac{\pi}{6}=\frac{1}{\sqrt{3}}\). Inverse values are found quickly from basic trigonometric values.क्योंकि \(\tan\frac{\pi}{6}=\frac{1}{\sqrt{3}}\) है। मूल त्रिकोणमितीय मानों से उल्टे मान जल्दी मिलते हैं।
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