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What is the principal value of \(\tan^{-1}\sqrt{3}\)?\(\tan^{-1}\sqrt{3}\) का प्रधान मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \(\frac{\pi}{3}\)\(\frac{\pi}{3}\)
Because \(\tan\frac{\pi}{3}=\sqrt{3}\) and \(\frac{\pi}{3}\) lies in the principal range. For \(\tan^{-1}\), take the angle in \(\left(-\frac{\pi}{2},\frac{\pi}{2}\right)\).क्योंकि \(\tan\frac{\pi}{3}=\sqrt{3}\) है और \(\frac{\pi}{3}\) प्रधान सीमा में है। \(\tan^{-1}\) में कोण \(\left(-\frac{\pi}{2},\frac{\pi}{2}\right)\) में लें।
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