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What is the value of \(\tan^{-1}\left(\tan\left(-\frac{\pi}{6}\right)\right)\)?\(\tan^{-1}\left(\tan\left(-\frac{\pi}{6}\right)\right)\) का मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \(-\frac{\pi}{6}\)\(-\frac{\pi}{6}\)
The angle \(-\frac{\pi}{6}\) lies in the principal range \(\left(-\frac{\pi}{2},\frac{\pi}{2}\right)\), so the value is the same. For \(\tan^{-1}\), the interval is open.\(-\frac{\pi}{6}\) प्रधान सीमा \(\left(-\frac{\pi}{2},\frac{\pi}{2}\right)\) में है इसलिए मान वही है। \(\tan^{-1}\) में सीमा खुली होती है।
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