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Which function is odd?कौन सा फलन विषम है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (\sin^{-1}x)(\sin^{-1}x)
Since (\sin^{-1}(-x)=-\sin^{-1}x), (\sin^{-1}x) is odd. The function (\tan^{-1}x) is also odd but is not in the options.(\sin^{-1}(-x)=-\sin^{-1}x) इसलिए (\sin^{-1}x) विषम है। (\tan^{-1}x) भी विषम होता है पर विकल्प में नहीं है।
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