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A student writes \(\sin^{-1}(\sin(5\pi/6))=5\pi/6\). What is the correct correction to this error?

Answer and explanation

Correct answer: \(\sin^{-1}(\sin(5\pi/6))=\pi/6\) because the principal value of \(\sin^{-1}\) lies in \([-\pi/2,\pi/2]\)

Since \(\sin(5\pi/6)=1/2\), we need the angle in the principal range \([-\pi/2,\pi/2]\) whose sine is \(1/2\). It is \(\pi/6\), not \(5\pi/6\). Exam tip: always check the principal-value range first.

Related tags

Inverse Trigonometric FunctionsPrincipal ValueInverse SineTrigonometryClass 12 MathematicsIntroduction To Inverse Trigonometric FunctionsMathematicsClass 12 Mcq

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