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Which statement is correct about \(\sin^{-1}2\)?

Answer and explanation

Correct answer: It is not defined in real numbers

The real-valued arcsin function \(\sin^{-1}x\) is defined only for \(x\in[-1,1]\). Since \(2\notin[-1,1]\), \(\sin^{-1}2\) is not defined as a real number. (Note: arcsin can be extended to complex values, but the question concerns real definition.) Exam tip: first check the domain of the inverse trigonometric function before evaluating.

Related tags

Inverse-Trigonometric-FunctionsDomainUndefinedArcsinDomain And RangeInverse Trigonometric FunctionsMathematicsClass 12 Mcq

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