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What is the domain of \(x\) for \(sin^{-1}(x^2-1)\)?\(sin^{-1}(x^2-1)\) के लिए \(x\) का डोमेन कौन-सा है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: ([-2,2])([-2,2])
From \(-1\le x^2-1\le1\), we get \(0\le x^2\le2\). Thus \(x\in[-\sqrt{2},\sqrt{2}]\), so none of the first three is exact.\(-1\le x^2-1\le1\) से \(0\le x^2\le2\) मिलता है। इसलिए \(x\in[-\sqrt{2},\sqrt{2}]\), जो दिए विकल्पों में नहीं है।
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