(\tan^{-1}\left(\tan\left\(-\frac{\pi}{6}\right\)\right)) का मान क्या है?
What is the value of (\tan^{-1}\left(\tan\left\(-\frac{\pi}{6}\right\)\right))?
Explanation opens after your attempt
Correct Answer
A. \(-\frac{\pi}{6}\)
Concept
The angle \(-\frac{\pi}{6}\) lies in the principal range (\left\(-\frac{\pi}{2},\frac{\pi}{2}\right\)), so the value is the same. For \(\tan^{-1}\), the interval is open.
Why this answer is correct
The correct answer is A. \(-\frac{\pi}{6}\). The angle \(-\frac{\pi}{6}\) lies in the principal range (\left\(-\frac{\pi}{2},\frac{\pi}{2}\right\)), so the value is the same. For \(\tan^{-1}\), the interval is open.
Exam Tip
\(-\frac{\pi}{6}\) प्रधान सीमा (\left\(-\frac{\pi}{2},\frac{\pi}{2}\right\)) में है इसलिए मान वही है। \(\tan^{-1}\) में सीमा खुली होती है।
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