यदि \(y=\tan^{-1}x\) हो तो सही संबंध कौन सा है?

If \(y=\tan^{-1}x\), which relation is correct?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

A. \(\tan y=x\) और (y\in\left\(-\frac{\pi}{2},\frac{\pi}{2}\right\))\(\tan y=x\) and (y\in\left\(-\frac{\pi}{2},\frac{\pi}{2}\right\))

Step 1

Concept

The expression \(y=\tan^{-1}x\) means \(\tan y=x\). Here (y) stays in the principal range (\left\(-\frac{\pi}{2},\frac{\pi}{2}\right\)).

Step 2

Why this answer is correct

The correct answer is A. \(\tan y=x\) और (y\in\left\(-\frac{\pi}{2},\frac{\pi}{2}\right\)) / \(\tan y=x\) and (y\in\left\(-\frac{\pi}{2},\frac{\pi}{2}\right\)). The expression \(y=\tan^{-1}x\) means \(\tan y=x\). Here (y) stays in the principal range (\left\(-\frac{\pi}{2},\frac{\pi}{2}\right\)).

Step 3

Exam Tip

\(y=\tan^{-1}x\) का मतलब \(\tan y=x\) होता है। यहां (y) प्रधान सीमा (\left\(-\frac{\pi}{2},\frac{\pi}{2}\right\)) में रहता है।

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Mathematics Answer, Explanation and Revision Hints

यदि \(y=\tan^{-1}x\) हो तो सही संबंध कौन सा है? / If \(y=\tan^{-1}x\), which relation is correct?

Correct Answer: A. \(\tan y=x\) और (y\in\left\(-\frac{\pi}{2},\frac{\pi}{2}\right\)) / \(\tan y=x\) and (y\in\left\(-\frac{\pi}{2},\frac{\pi}{2}\right\)). Explanation: \(y=\tan^{-1}x\) का मतलब \(\tan y=x\) होता है। यहां (y) प्रधान सीमा (\left\(-\frac{\pi}{2},\frac{\pi}{2}\right\)) में रहता है। / The expression \(y=\tan^{-1}x\) means \(\tan y=x\). Here (y) stays in the principal range (\left\(-\frac{\pi}{2},\frac{\pi}{2}\right\)).

Which concept should I revise for this Mathematics MCQ?

The expression \(y=\tan^{-1}x\) means \(\tan y=x\). Here (y) stays in the principal range (\left\(-\frac{\pi}{2},\frac{\pi}{2}\right\)).

What exam hint can help solve this Mathematics question?

\(y=\tan^{-1}x\) का मतलब \(\tan y=x\) होता है। यहां (y) प्रधान सीमा (\left\(-\frac{\pi}{2},\frac{\pi}{2}\right\)) में रहता है।