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Colligative Properties

Class 12 Chemistry के इस tag से जुड़े questions। हर question के साथ chapter, topic, level और difficulty दी गई है।

ChemistryWhen 4 g of a solute is dissolved in 500 g of water, the depression in freezing point is 0.279 K. If the van’t Hoff factor is 1.5, what is the true molar mass?Class 12Chapter 01: Solutions6: Molar Mass DeterminationLevel 16Medium ChemistryA 0.05 M solution has osmotic pressure 1.845 atm at 300 K. If the true molar mass of the solute is 120 g mol−1, what observed molar mass will be obtained from the colligative method?Class 12Chapter 01: Solutions5: Colligative PropertiesLevel 16Hard ChemistryThe true molar mass of AlCl3 is 133.5 g mol−1. If the observed molar mass from a colligative method is 44.5 g mol−1, what is the degree of dissociation?Class 12Chapter 01: Solutions5: Colligative PropertiesLevel 16Hard ChemistryA solution contains 4.0 g of solute in 250 g of solvent. If Kf = 2.0 K kg mol⁻¹ and the freezing-point depression is 0.4 K, what is the molar mass of the solute?Class 12Chapter 01: Solutions6: Molar Mass DeterminationLevel 18Medium ChemistryA 1.0 L solution is prepared by dissolving 2.2 g of a substance. Its osmotic pressure at 300 K is 0.451 atm. If R = 0.082 L atm K⁻¹ mol⁻¹, what is the approximate molar mass of the substance?Class 12Chapter 01: Solutions6: Molar Mass DeterminationLevel 18Medium ChemistryWhen 1.6 g of a substance is dissolved in 200 g of water, the freezing-point depression is 0.744 K. If the normal molar mass is 80 g mol⁻¹ and Kf = 1.86 K kg mol⁻¹, what is the van’t Hoff factor i?Class 12Chapter 01: Solutions6: Molar Mass DeterminationLevel 18Hard ChemistryA solution contains 0.6 g of a solute in 0.2 L of solution. If its osmotic pressure at 300 K is 0.369 atm, what is the molar mass? Use R = 0.082 L atm K⁻¹ mol⁻¹.Class 12Chapter 01: Solutions6: Molar Mass DeterminationLevel 18Hard ChemistryIn a boiling-point elevation problem, w₂ = 2.0 g solute, w₁ = 400 g solvent, Kb = 0.52 K kg mol⁻¹, and ΔTb = 0.026 K. What is the molar mass of the solute?Class 12Chapter 01: Solutions6: Molar Mass DeterminationLevel 18Hard ChemistryA solution contains 1.0 g solute in 100 g water. If Kf = 1.86 K kg mol⁻¹, the depression in freezing point is 0.093 K, and the normal molar mass is 100 g mol⁻¹, what is the van’t Hoff factor?Class 12Chapter 01: Solutions5: Colligative PropertiesLevel 18Hard ChemistryWhen 1.5 g of a non-electrolyte substance is dissolved in 250 g of a solvent, the depression in freezing point is 0.1116 K. If the cryoscopic constant of the solvent is 1.86 K kg mol⁻¹, what is the molar mass of the substance?Class 12Chapter 01: Solutions6: Molar Mass DeterminationLevel 18Medium ChemistryA 3.0 g solute dissolved in 100 g solvent forms a 0.3 m solution. If the solution shows i = 2 in colligative-property measurements, what is its effective molality?Class 12Chapter 01: Solutions5: Colligative PropertiesLevel 18Medium ChemistryIf a 0.2 M nonelectrolyte solution has an osmotic pressure of 4.92 atm at 300 K, what will be the osmotic pressure of a 0.1 M solute with i = 3 at the same temperature?Class 12Chapter 01: Solutions7: Abnormal Molecular MassLevel 18Medium ChemistryA polymer solution contains 0.2 g polymer in 200 mL solution. At 300 K, its osmotic pressure is 0.0205 atm. If R = 0.082 L atm K⁻¹ mol⁻¹, what is the molar mass of the polymer?Class 12Chapter 01: Solutions6: Molar Mass DeterminationLevel 18Medium ChemistryIn the vapour-pressure-lowering method, 1.8 g of a solute is dissolved in 9.0 g water. The relative lowering of vapour pressure is 0.10. If the molar mass of water is 18 g mol⁻¹, what is the approximate molar mass of the solute?Class 12Chapter 01: Solutions6: Molar Mass DeterminationLevel 18Medium ChemistryA 250 mL solution is prepared using 0.25 g of a polymer. Its osmotic pressure at 300 K is 0.041 atm. If R = 0.082 L atm K−1 mol−1, what is the molar mass of the polymer?Class 12Chapter 01: Solutions6: Molar Mass DeterminationLevel 18Hard ChemistryA 2.5 g solute dissolved in 125 g of solvent produces a boiling-point elevation of 0.26 K. If Kb = 0.52 K kg mol−1, what is the molar mass of the solute?Class 12Chapter 01: Solutions6: Molar Mass DeterminationLevel 18Hard ChemistryWhen 1.8 g of a nonelectrolyte is dissolved in 150 g of solvent, the depression in freezing point is 0.372 K. For the solvent, Kf = 1.86 K kg mol−1. What is the molar mass of the solute?Class 12Chapter 01: Solutions6: Molar Mass DeterminationLevel 18Hard ChemistryIf 60% of the molecules of a substance form trimers and its normal molar mass is 90 g mol−1, what will be the observed molar mass?Class 12Chapter 01: Solutions7: Abnormal Molecular MassLevel 18Hard ChemistryFor the same solute, 1.0 g dissolved in 100 g of solvent gives ΔTf = 0.186 K. If 2.0 g of the same solute is dissolved in 250 g of the same solvent, what will be the new value of ΔTf?Class 12Chapter 01: Solutions6: Molar Mass DeterminationLevel 18Medium ChemistryWhen 4.0 g of a substance is dissolved in 200 g of water, ΔTf = 0.372 K. If its normal molar mass is 100 g mol−1 and Kf = 1.86 K kg mol−1, what is the van’t Hoff factor i in the solution?Class 12Chapter 01: Solutions7: Abnormal Molecular MassLevel 18Hard