यदि शुद्ध विलायक का हिमांक \(5^\circ C\) है और \(\Delta T_f = 2^\circ C\) है, तो विलयन का हिमांक क्या होगा?
If the freezing point of pure solvent is \(5^\circ C\) and \(\Delta T_f = 2^\circ C\), what is the freezing point of the solution?
Explanation opens after your attempt
A. \(3^\circ C\)
Concept
हिमांक में कमी में ताप घटता है। / In freezing point depression, temperature decreases.
Why this answer is correct
\(5^\circ C - 2^\circ C = 3^\circ C\)। / \(5^\circ C - 2^\circ C = 3^\circ C\).
Exam Tip
हिमांक वाले प्रश्न में \(\Delta T_f\) को घटाएं। / In freezing point questions, subtract \(\Delta T_f\).
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