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If a 0.02 M solution has a volume of 1 L, how many moles of solute are present?

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Answer and explanation

Correct answer: 0.02 mol

Molarity is defined as the number of moles of solute present in one litre of solution: M = n/V. Rearranging gives n = M × V. Substituting the given values, n = 0.02 mol L⁻¹ × 1 L = 0.02 mol. The litre units cancel, leaving moles. Therefore, option B is correct. Always ensure that volume is expressed in litres when using molarity.

Related tags

MolarityNumber Of MolesSolution ConcentrationSolutions2: Concentration MetricsConcentration MetricsChapter 01: SolutionsChapter 01 Solutions

Frequently asked questions

What is the correct answer to this question?

0.02 mol

Why is this the correct answer?

Molarity is defined as the number of moles of solute present in one litre of solution: M = n/V. Rearranging gives n = M × V. Substituting the given values, n = 0.02 mol L⁻¹ × 1 L = 0.02 mol. The litre units cancel, leaving moles. Therefore, option B is correct. Always ensure that volume is expressed in litres when using molarity.

Which subject and chapter does this question cover?

This is a Class 12 Chemistry question. Chapter: Chapter 01: Solutions. Topic: 2: Concentration Metrics.

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