01 If a gas has a higher Henry's law constant, how will its solubility be at the same pressure and temperature?
Answer and explanation
Correct answer: B. कम होगी
Explanation: Using the concentration form of Henry’s law, p = K_H x, the mole fraction of dissolved gas is x = p/K_H. At the same pressure, increasing K_H therefore decreases x, so less gas dissolves. Thus, a gas with a higher Henry’s law constant has lower solubility. It is not correct to say that its solubility is zero or independent of pressure.