असमानता \( 2-\frac{3x-1}{4}<\frac{x+2}{3} \) का हल कौन-सा है?

Which is the solution of \( 2-\frac{3x-1}{4}<\frac{x+2}{3} \)?

Explanation opens after your attempt
Correct Answer

A. \(x>\frac{14}{13}\)

Step 1

Concept

Multiplying by (12) gives (24-9x+3<4x+8). Thus (19<13x) and \(x>\frac{19}{13}\).

Step 2

Why this answer is correct

The correct answer is A. \(x>\frac{14}{13}\). Multiplying by (12) gives (24-9x+3<4x+8). Thus (19<13x) and \(x>\frac{19}{13}\).

Step 3

Exam Tip

(12) से गुणा करने पर (24-9x+3<4x+8) मिलता है। इससे (19<13x) और \(x>\frac{19}{13}\) है।

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Mathematics Answer, Explanation and Revision Hints

असमानता \( 2-\frac{3x-1}{4}<\frac{x+2}{3} \) का हल कौन-सा है? / Which is the solution of \( 2-\frac{3x-1}{4}<\frac{x+2}{3} \)?

Correct Answer: A. \(x>\frac{14}{13}\). Explanation: (12) से गुणा करने पर (24-9x+3<4x+8) मिलता है। इससे (19<13x) और \(x>\frac{19}{13}\) है। / Multiplying by (12) gives (24-9x+3<4x+8). Thus (19<13x) and \(x>\frac{19}{13}\).

Which concept should I revise for this Mathematics MCQ?

Multiplying by (12) gives (24-9x+3<4x+8). Thus (19<13x) and \(x>\frac{19}{13}\).

What exam hint can help solve this Mathematics question?

(12) से गुणा करने पर (24-9x+3<4x+8) मिलता है। इससे (19<13x) और \(x>\frac{19}{13}\) है।