प्रणाली \(2x+3y\le 18\), \(x+y\ge 4\), \(x\ge 0\), \(y\ge 0\) का हल क्षेत्र कैसा है?

What is the solution region of \(2x+3y\le 18\), \(x+y\ge 4\), \(x\ge 0\), \(y\ge 0\)?

Explanation opens after your attempt
Correct Answer

A. सीमितBounded

Step 1

Concept

The upper bound \(2x+3y\le 18\) and the first quadrant make the region bounded. The lower line \(x+y\ge 4\) only cuts an inner part.

Step 2

Why this answer is correct

The correct answer is A. सीमित / Bounded. The upper bound \(2x+3y\le 18\) and the first quadrant make the region bounded. The lower line \(x+y\ge 4\) only cuts an inner part.

Step 3

Exam Tip

ऊपरी सीमा \(2x+3y\le 18\) और प्रथम चतुर्थांश क्षेत्र को सीमित करते हैं। निचली रेखा \(x+y\ge 4\) केवल अंदर का हिस्सा काटती है।

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Mathematics Answer, Explanation and Revision Hints

प्रणाली \(2x+3y\le 18\), \(x+y\ge 4\), \(x\ge 0\), \(y\ge 0\) का हल क्षेत्र कैसा है? / What is the solution region of \(2x+3y\le 18\), \(x+y\ge 4\), \(x\ge 0\), \(y\ge 0\)?

Correct Answer: A. सीमित / Bounded. Explanation: ऊपरी सीमा \(2x+3y\le 18\) और प्रथम चतुर्थांश क्षेत्र को सीमित करते हैं। निचली रेखा \(x+y\ge 4\) केवल अंदर का हिस्सा काटती है। / The upper bound \(2x+3y\le 18\) and the first quadrant make the region bounded. The lower line \(x+y\ge 4\) only cuts an inner part.

Which concept should I revise for this Mathematics MCQ?

The upper bound \(2x+3y\le 18\) and the first quadrant make the region bounded. The lower line \(x+y\ge 4\) only cuts an inner part.

What exam hint can help solve this Mathematics question?

ऊपरी सीमा \(2x+3y\le 18\) और प्रथम चतुर्थांश क्षेत्र को सीमित करते हैं। निचली रेखा \(x+y\ge 4\) केवल अंदर का हिस्सा काटती है।