असमानता (7(x-2)<2x+13) का हल क्या है?

What is the solution of the inequality (7(x-2)<2x+13)?

Explanation opens after your attempt
Correct Answer

A. \(x<\frac{27}{5}\)

Step 1

Concept

Opening brackets gives (7x-14<2x+13), so (5x<27) and \(x<\frac{27}{5}\). A fractional answer can also be correct.

Step 2

Why this answer is correct

The correct answer is A. \(x<\frac{27}{5}\). Opening brackets gives (7x-14<2x+13), so (5x<27) and \(x<\frac{27}{5}\). A fractional answer can also be correct.

Step 3

Exam Tip

कोष्ठक खोलने पर (7x-14<2x+13), इसलिए (5x<27) और \(x<\frac{27}{5}\)। भिन्न उत्तर भी सही हल हो सकता है।

Question me issue ya doubt hai?

Answer, explanation, typing mistake ya suggestion directly hamari team ko bhejein. 📱Helpline (Call / WhatsApp): +91 7272824365

Related Mathematics Questions

FAQs

Mathematics Answer, Explanation and Revision Hints

असमानता (7(x-2)<2x+13) का हल क्या है? / What is the solution of the inequality (7(x-2)<2x+13)?

Correct Answer: A. \(x<\frac{27}{5}\). Explanation: कोष्ठक खोलने पर (7x-14<2x+13), इसलिए (5x<27) और \(x<\frac{27}{5}\)। भिन्न उत्तर भी सही हल हो सकता है। / Opening brackets gives (7x-14<2x+13), so (5x<27) and \(x<\frac{27}{5}\). A fractional answer can also be correct.

Which concept should I revise for this Mathematics MCQ?

Opening brackets gives (7x-14<2x+13), so (5x<27) and \(x<\frac{27}{5}\). A fractional answer can also be correct.

What exam hint can help solve this Mathematics question?

कोष्ठक खोलने पर (7x-14<2x+13), इसलिए (5x<27) और \(x<\frac{27}{5}\)। भिन्न उत्तर भी सही हल हो सकता है।