फलन (f(x)=\sqrt{x+2}-4) के ग्राफ का परिसर क्या है?

What is the range of the graph of (f(x)=\sqrt{x+2}-4)?

Explanation opens after your attempt
Correct Answer

A. \([-4,\infty\))

Step 1

Concept

Since \(\sqrt{x+2}\ge0\), (f(x)\ge -4). In exams, take the square-root minimum (0) and add the vertical shift.

Step 2

Why this answer is correct

The correct answer is A. \([-4,\infty\)). Since \(\sqrt{x+2}\ge0\), (f(x)\ge -4). In exams, take the square-root minimum (0) and add the vertical shift.

Step 3

Exam Tip

\(\sqrt{x+2}\ge0\) इसलिए (f(x)\ge -4)। परीक्षा में वर्गमूल का न्यूनतम (0) लेकर ऊर्ध्व विस्थापन जोड़ें।

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फलन (f(x)=\sqrt{x+2}-4) के ग्राफ का परिसर क्या है? / What is the range of the graph of (f(x)=\sqrt{x+2}-4)?

Correct Answer: A. \([-4,\infty\)). Explanation: \(\sqrt{x+2}\ge0\) इसलिए (f(x)\ge -4)। परीक्षा में वर्गमूल का न्यूनतम (0) लेकर ऊर्ध्व विस्थापन जोड़ें। / Since \(\sqrt{x+2}\ge0\), (f(x)\ge -4). In exams, take the square-root minimum (0) and add the vertical shift.

Which concept should I revise for this Mathematics MCQ?

Since \(\sqrt{x+2}\ge0\), (f(x)\ge -4). In exams, take the square-root minimum (0) and add the vertical shift.

What exam hint can help solve this Mathematics question?

\(\sqrt{x+2}\ge0\) इसलिए (f(x)\ge -4)। परीक्षा में वर्गमूल का न्यूनतम (0) लेकर ऊर्ध्व विस्थापन जोड़ें।