(\sum_{r=0}^{n} (-1)^r{}^{n}C_r=0) किस substitution से जुड़ा है?

The identity (\sum_{r=0}^{n} (-1)^r{}^{n}C_r=0) is connected with which substitution?

Explanation opens after your attempt
Correct Answer

C. ((1+x)^n) में (x=-1)(x=-1) in ((1+x)^n)

Step 1

Concept

Putting (x=-1) gives ((1-1)^n=0). In exams think of (x=-1) for alternating binomial sums.

Step 2

Why this answer is correct

The correct answer is C. ((1+x)^n) में (x=-1) / (x=-1) in ((1+x)^n). Putting (x=-1) gives ((1-1)^n=0). In exams think of (x=-1) for alternating binomial sums.

Step 3

Exam Tip

(x=-1) रखने पर ((1-1)^n=0) मिलता है। परीक्षा में alternating binomial sum में (x=-1) सोचें।

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Mathematics Answer, Explanation and Revision Hints

(\sum_{r=0}^{n} (-1)^r{}^{n}C_r=0) किस substitution से जुड़ा है? / The identity (\sum_{r=0}^{n} (-1)^r{}^{n}C_r=0) is connected with which substitution?

Correct Answer: C. ((1+x)^n) में (x=-1) / (x=-1) in ((1+x)^n). Explanation: (x=-1) रखने पर ((1-1)^n=0) मिलता है। परीक्षा में alternating binomial sum में (x=-1) सोचें। / Putting (x=-1) gives ((1-1)^n=0). In exams think of (x=-1) for alternating binomial sums.

Which concept should I revise for this Mathematics MCQ?

Putting (x=-1) gives ((1-1)^n=0). In exams think of (x=-1) for alternating binomial sums.

What exam hint can help solve this Mathematics question?

(x=-1) रखने पर ((1-1)^n=0) मिलता है। परीक्षा में alternating binomial sum में (x=-1) सोचें।