\( \frac{4\pi}{9} \) रेडियन की अंतिम भुजा किस चतुर्थांश में होगी?
In which quadrant will the terminal side of \( \frac{4\pi}{9} \) radians lie?
Explanation opens after your attempt
A. प्रथम चतुर्थांशFirst quadrant
Concept
\(0<\frac{4\pi}{9}<\frac{\pi}{2}\), so it lies in the first quadrant. Check the interval of small positive radian angles carefully.
Why this answer is correct
The correct answer is A. प्रथम चतुर्थांश / First quadrant. \(0<\frac{4\pi}{9}<\frac{\pi}{2}\), so it lies in the first quadrant. Check the interval of small positive radian angles carefully.
Exam Tip
\(0<\frac{4\pi}{9}<\frac{\pi}{2}\) है इसलिए यह प्रथम चतुर्थांश में है। छोटे धनात्मक रेडियन कोणों की सीमा ध्यान से देखें।
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