हल-क्षेत्र \(x+y\geq 6\), \(2x+y\geq 7\), \(0\leq x\leq 4\), \(y\geq 0\) में (y) का न्यूनतम मान क्या है?

In the solution region \(x+y\geq 6\), \(2x+y\geq 7\), \(0\leq x\leq 4\), and \(y\geq 0\), what is the minimum value of (y)?

Explanation opens after your attempt
Correct Answer

B. (2)

Step 1

Concept

To minimize (y), take the maximum allowed (x=4). Then \(x+y\geq 6\) gives \(y\geq 2\).

Step 2

Why this answer is correct

The correct answer is B. (2). To minimize (y), take the maximum allowed (x=4). Then \(x+y\geq 6\) gives \(y\geq 2\).

Step 3

Exam Tip

(y) को न्यूनतम करने के लिए (x) को अधिकतम (4) लें। तब \(x+y\geq 6\) से \(y\geq 2\) मिलता है।

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Mathematics Answer, Explanation and Revision Hints

हल-क्षेत्र \(x+y\geq 6\), \(2x+y\geq 7\), \(0\leq x\leq 4\), \(y\geq 0\) में (y) का न्यूनतम मान क्या है? / In the solution region \(x+y\geq 6\), \(2x+y\geq 7\), \(0\leq x\leq 4\), and \(y\geq 0\), what is the minimum value of (y)?

Correct Answer: B. (2). Explanation: (y) को न्यूनतम करने के लिए (x) को अधिकतम (4) लें। तब \(x+y\geq 6\) से \(y\geq 2\) मिलता है। / To minimize (y), take the maximum allowed (x=4). Then \(x+y\geq 6\) gives \(y\geq 2\).

Which concept should I revise for this Mathematics MCQ?

To minimize (y), take the maximum allowed (x=4). Then \(x+y\geq 6\) gives \(y\geq 2\).

What exam hint can help solve this Mathematics question?

(y) को न्यूनतम करने के लिए (x) को अधिकतम (4) लें। तब \(x+y\geq 6\) से \(y\geq 2\) मिलता है।