यदि \(U={1,2,\ldots,50}\), \(A={x:x\in U,;2\mid x}\), \(B={x:x\in U,;5\mid x}\), तो \(A\setminus B\) में कितने तत्व हैं?
If \(U={1,2,\ldots,50}\), \(A={x:x\in U,;2\mid x}\), \(B={x:x\in U,;5\mid x}\), how many elements are in \(A\setminus B\)?
Explanation opens after your attempt
Correct Answer
A. (20)
Concept
There are (25) even numbers in (A), and (5) of them are also divisible by (10). Therefore (25-5=20) elements remain.
Why this answer is correct
The correct answer is A. (20). There are (25) even numbers in (A), and (5) of them are also divisible by (10). Therefore (25-5=20) elements remain.
Exam Tip
(A) में (25) सम संख्याएँ हैं और (10) से विभाज्य (5) संख्याएँ (B) में भी हैं। इसलिए (25-5=20) तत्व बचते हैं।
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