यदि \(U={1,2,\ldots,100}\), \(A={x:x\in U,;4\mid x}\) और \(B={x:x\in U,;10\mid x}\), तो \(|A\cap B|\) क्या है?

If \(U={1,2,\ldots,100}\), \(A={x:x\in U,;4\mid x}\) and \(B={x:x\in U,;10\mid x}\), what is \(|A\cap B|\)?

Explanation opens after your attempt
Correct Answer

A. (5)

Step 1

Concept

Common numbers must be divisible by the least common multiple (20) of (4) and (10). There are (5) such numbers up to (100).

Step 2

Why this answer is correct

The correct answer is A. (5). Common numbers must be divisible by the least common multiple (20) of (4) and (10). There are (5) such numbers up to (100).

Step 3

Exam Tip

सामान्य संख्याएँ (4) और (10) के लघुत्तम समापवर्त्य (20) से विभाज्य होंगी। (100) तक ऐसी (5) संख्याएँ हैं।

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यदि \(U={1,2,\ldots,100}\), \(A={x:x\in U,;4\mid x}\) और \(B={x:x\in U,;10\mid x}\), तो \(|A\cap B|\) क्या है? / If \(U={1,2,\ldots,100}\), \(A={x:x\in U,;4\mid x}\) and \(B={x:x\in U,;10\mid x}\), what is \(|A\cap B|\)?

Correct Answer: A. (5). Explanation: सामान्य संख्याएँ (4) और (10) के लघुत्तम समापवर्त्य (20) से विभाज्य होंगी। (100) तक ऐसी (5) संख्याएँ हैं। / Common numbers must be divisible by the least common multiple (20) of (4) and (10). There are (5) such numbers up to (100).

Which concept should I revise for this Mathematics MCQ?

Common numbers must be divisible by the least common multiple (20) of (4) and (10). There are (5) such numbers up to (100).

What exam hint can help solve this Mathematics question?

सामान्य संख्याएँ (4) और (10) के लघुत्तम समापवर्त्य (20) से विभाज्य होंगी। (100) तक ऐसी (5) संख्याएँ हैं।