यदि (r=9) सेमी और त्रिज्यखंड का क्षेत्रफल \( \frac{81\pi}{8} \) वर्ग सेमी है तो केंद्र कोण डिग्री में क्या होगा?
If (r=9) cm and the sector area is \( \frac{81\pi}{8} \) square cm, what is the central angle in degrees?
Explanation opens after your attempt
B. \(45^\circ\)
Concept
From \( \frac{81\pi}{8}=\frac{1}{2}\times81\times\theta \), \( \theta=\frac{\pi}{4}=45^\circ \). The angle from the sector area formula is in radians.
Why this answer is correct
The correct answer is B. \(45^\circ\). From \( \frac{81\pi}{8}=\frac{1}{2}\times81\times\theta \), \( \theta=\frac{\pi}{4}=45^\circ \). The angle from the sector area formula is in radians.
Exam Tip
\( \frac{81\pi}{8}=\frac{1}{2}\times81\times\theta \) से \( \theta=\frac{\pi}{4}=45^\circ \) है। क्षेत्रफल सूत्र में कोण रेडियन में निकलता है।
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