यदि \(^{n}P_r=r!,{}^{n}C_r\), तो \(^{n}P_r\) हमेशा \(^{n}C_r\) से बड़ा या बराबर क्यों होता है?
If \(^{n}P_r=r!,{}^{n}C_r\), why is \(^{n}P_r\) always greater than or equal to \(^{n}C_r\)?
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Correct Answer
A. क्योंकि \(r!\geq1\) होता हैBecause \(r!\geq1\)
Concept
Permutation counts all orders of each selected group. In exams equality is also possible for (r=0) or (r=1).
Why this answer is correct
The correct answer is A. क्योंकि \(r!\geq1\) होता है / Because \(r!\geq1\). Permutation counts all orders of each selected group. In exams equality is also possible for (r=0) or (r=1).
Exam Tip
Permutation हर selected group के all orders गिनता है। परीक्षा में (r=0) या (r=1) पर equality भी संभव है।
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