यदि (\frac{(n+1)!}{(n-1)!}=30) हो, तो (n) का मान क्या है?

If (\frac{(n+1)!}{(n-1)!}=30), what is the value of (n)?

Explanation opens after your attempt
Correct Answer

B. (5)

Step 1

Concept

(\frac{(n+1)!}{(n-1)!}=n(n+1)), so (n(n+1)=30) gives (n=5). Reduce factorials first in such questions.

Step 2

Why this answer is correct

The correct answer is B. (5). (\frac{(n+1)!}{(n-1)!}=n(n+1)), so (n(n+1)=30) gives (n=5). Reduce factorials first in such questions.

Step 3

Exam Tip

(\frac{(n+1)!}{(n-1)!}=n(n+1)), इसलिए (n(n+1)=30) से (n=5)। ऐसे प्रश्नों में पहले फैक्टोरियल घटाएं।

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Mathematics Answer, Explanation and Revision Hints

यदि (\frac{(n+1)!}{(n-1)!}=30) हो, तो (n) का मान क्या है? / If (\frac{(n+1)!}{(n-1)!}=30), what is the value of (n)?

Correct Answer: B. (5). Explanation: (\frac{(n+1)!}{(n-1)!}=n(n+1)), इसलिए (n(n+1)=30) से (n=5)। ऐसे प्रश्नों में पहले फैक्टोरियल घटाएं। / (\frac{(n+1)!}{(n-1)!}=n(n+1)), so (n(n+1)=30) gives (n=5). Reduce factorials first in such questions.

Which concept should I revise for this Mathematics MCQ?

(\frac{(n+1)!}{(n-1)!}=n(n+1)), so (n(n+1)=30) gives (n=5). Reduce factorials first in such questions.

What exam hint can help solve this Mathematics question?

(\frac{(n+1)!}{(n-1)!}=n(n+1)), इसलिए (n(n+1)=30) से (n=5)। ऐसे प्रश्नों में पहले फैक्टोरियल घटाएं।