यदि clockwise और anticlockwise arrangements को same माना जाए तो (n) अलग beads की necklace count किस रूप से जुड़ती है?

If clockwise and anticlockwise arrangements are considered same the necklace count of (n) distinct beads is connected with which form?

Explanation opens after your attempt
Correct Answer

C. (\frac{(n-1)!}{2})

Step 1

Concept

First removing rotations gives ((n-1)!) and then same reflection makes us divide by (2). In exams check both rotation and reflection in necklaces.

Step 2

Why this answer is correct

The correct answer is C. (\frac{(n-1)!}{2}). First removing rotations gives ((n-1)!) and then same reflection makes us divide by (2). In exams check both rotation and reflection in necklaces.

Step 3

Exam Tip

पहले rotations हटाकर ((n-1)!) मिलता है फिर reflection same होने से (2) से भाग देते हैं। परीक्षा में necklace में rotation और reflection दोनों देखें।

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Mathematics Answer, Explanation and Revision Hints

यदि clockwise और anticlockwise arrangements को same माना जाए तो (n) अलग beads की necklace count किस रूप से जुड़ती है? / If clockwise and anticlockwise arrangements are considered same the necklace count of (n) distinct beads is connected with which form?

Correct Answer: C. (\frac{(n-1)!}{2}). Explanation: पहले rotations हटाकर ((n-1)!) मिलता है फिर reflection same होने से (2) से भाग देते हैं। परीक्षा में necklace में rotation और reflection दोनों देखें। / First removing rotations gives ((n-1)!) and then same reflection makes us divide by (2). In exams check both rotation and reflection in necklaces.

Which concept should I revise for this Mathematics MCQ?

First removing rotations gives ((n-1)!) and then same reflection makes us divide by (2). In exams check both rotation and reflection in necklaces.

What exam hint can help solve this Mathematics question?

पहले rotations हटाकर ((n-1)!) मिलता है फिर reflection same होने से (2) से भाग देते हैं। परीक्षा में necklace में rotation और reflection दोनों देखें।