यदि \(A={x:x\in \mathbb{Z},-2\le x\le 3}\) और \(B={x:x\in \mathbb{Z},0\le x\le 5}\) हैं, तो \(A\cap B\) क्या है?

If \(A={x:x\in \mathbb{Z},-2\le x\le 3}\) and \(B={x:x\in \mathbb{Z},0\le x\le 5}\), what is \(A\cap B\)?

Explanation opens after your attempt
Correct Answer

B. ( {0,1,2,3} )

Step 1

Concept

The common integers in both intervals are (0,1,2,3). It is useful to convert inequalities into roster form first.

Step 2

Why this answer is correct

The correct answer is B. ( {0,1,2,3} ). The common integers in both intervals are (0,1,2,3). It is useful to convert inequalities into roster form first.

Step 3

Exam Tip

दोनों अंतरालों में समान पूर्णांक (0,1,2,3) हैं। असमानताओं को पहले सूची रूप में बदलना उपयोगी है।

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Mathematics Answer, Explanation and Revision Hints

यदि \(A={x:x\in \mathbb{Z},-2\le x\le 3}\) और \(B={x:x\in \mathbb{Z},0\le x\le 5}\) हैं, तो \(A\cap B\) क्या है? / If \(A={x:x\in \mathbb{Z},-2\le x\le 3}\) and \(B={x:x\in \mathbb{Z},0\le x\le 5}\), what is \(A\cap B\)?

Correct Answer: B. ( {0,1,2,3} ). Explanation: दोनों अंतरालों में समान पूर्णांक (0,1,2,3) हैं। असमानताओं को पहले सूची रूप में बदलना उपयोगी है। / The common integers in both intervals are (0,1,2,3). It is useful to convert inequalities into roster form first.

Which concept should I revise for this Mathematics MCQ?

The common integers in both intervals are (0,1,2,3). It is useful to convert inequalities into roster form first.

What exam hint can help solve this Mathematics question?

दोनों अंतरालों में समान पूर्णांक (0,1,2,3) हैं। असमानताओं को पहले सूची रूप में बदलना उपयोगी है।