यदि \(A=\{1,2,3,4,5,6\}\) है, तो (\mathcal{P}(A)) में (3) तत्वों वाले subsets में से कितने (1) को रखते हैं?

If \(A=\{1,2,3,4,5,6\}\), among the (3)-element subsets in (\mathcal{P}(A)), how many contain (1)?

Explanation opens after your attempt
Correct Answer

B. (10)

Step 1

Concept

(1) is fixed, so the remaining (2) elements are chosen from (5): \(\binom{5}{2}=10\). In exams, count remaining choices after fixing the compulsory element.

Step 2

Why this answer is correct

The correct answer is B. (10). (1) is fixed, so the remaining (2) elements are chosen from (5): \(\binom{5}{2}=10\). In exams, count remaining choices after fixing the compulsory element.

Step 3

Exam Tip

(1) fixed है, इसलिए बाकी (2) तत्व (5) में से चुने जाएंगे: \(\binom{5}{2}=10\)। परीक्षा में compulsory element के बाद remaining choice गिनें।

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Mathematics Answer, Explanation and Revision Hints

यदि \(A=\{1,2,3,4,5,6\}\) है, तो (\mathcal{P}(A)) में (3) तत्वों वाले subsets में से कितने (1) को रखते हैं? / If \(A=\{1,2,3,4,5,6\}\), among the (3)-element subsets in (\mathcal{P}(A)), how many contain (1)?

Correct Answer: B. (10). Explanation: (1) fixed है, इसलिए बाकी (2) तत्व (5) में से चुने जाएंगे: \(\binom{5}{2}=10\)। परीक्षा में compulsory element के बाद remaining choice गिनें। / (1) is fixed, so the remaining (2) elements are chosen from (5): \(\binom{5}{2}=10\). In exams, count remaining choices after fixing the compulsory element.

Which concept should I revise for this Mathematics MCQ?

(1) is fixed, so the remaining (2) elements are chosen from (5): \(\binom{5}{2}=10\). In exams, count remaining choices after fixing the compulsory element.

What exam hint can help solve this Mathematics question?

(1) fixed है, इसलिए बाकी (2) तत्व (5) में से चुने जाएंगे: \(\binom{5}{2}=10\)। परीक्षा में compulsory element के बाद remaining choice गिनें।