ग्राफ \(y=x^2\) और (y=6-x) किस (x) मानों पर प्रतिच्छेद करते हैं?

At which (x) values do the graphs \(y=x^2\) and (y=6-x) intersect?

Explanation opens after your attempt
Correct Answer

A. (x=-3,2)

Step 1

Concept

For intersection, set \(x^2=6-x\). From \(x^2+x-6=0\), we get (x=-3,2).

Step 2

Why this answer is correct

The correct answer is A. (x=-3,2). For intersection, set \(x^2=6-x\). From \(x^2+x-6=0\), we get (x=-3,2).

Step 3

Exam Tip

प्रतिच्छेद के लिए \(x^2=6-x\) रखें। \(x^2+x-6=0\) से (x=-3,2) मिलते हैं।

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Mathematics Answer, Explanation and Revision Hints

ग्राफ \(y=x^2\) और (y=6-x) किस (x) मानों पर प्रतिच्छेद करते हैं? / At which (x) values do the graphs \(y=x^2\) and (y=6-x) intersect?

Correct Answer: A. (x=-3,2). Explanation: प्रतिच्छेद के लिए \(x^2=6-x\) रखें। \(x^2+x-6=0\) से (x=-3,2) मिलते हैं। / For intersection, set \(x^2=6-x\). From \(x^2+x-6=0\), we get (x=-3,2).

Which concept should I revise for this Mathematics MCQ?

For intersection, set \(x^2=6-x\). From \(x^2+x-6=0\), we get (x=-3,2).

What exam hint can help solve this Mathematics question?

प्रतिच्छेद के लिए \(x^2=6-x\) रखें। \(x^2+x-6=0\) से (x=-3,2) मिलते हैं।