\( \theta=\frac{13\pi}{6} \) का मुख्य सहसमापी कोण निकालने के बाद संदर्भ कोण क्या होगा?
After finding the principal coterminal angle of \( \theta=\frac{13\pi}{6} \), what will be the reference angle?
Explanation opens after your attempt
A. \( \frac{\pi}{6} \)
Concept
\( \frac{13\pi}{6}-2\pi=\frac{\pi}{6} \), and it is in the first quadrant. First find the principal angle and then the reference angle.
Why this answer is correct
The correct answer is A. \( \frac{\pi}{6} \). \( \frac{13\pi}{6}-2\pi=\frac{\pi}{6} \), and it is in the first quadrant. First find the principal angle and then the reference angle.
Exam Tip
\( \frac{13\pi}{6}-2\pi=\frac{\pi}{6} \) है और यह प्रथम चतुर्थांश में है। पहले मुख्य कोण फिर संदर्भ कोण निकालें।
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