यदि हवा में वास्तविक वाष्प दाब (15) और (RH=75%) हो तो \(e_s\) कितना होगा?
If actual vapour pressure is (15) and (RH=75%), what will \(e_s\) be?
Explanation opens after your attempt
A. (20)
Concept
\(e_s=\frac{e\times100}{RH}=\frac{15\times100}{75}=20\). Exam tip: handle (RH) as a percentage carefully.
Why this answer is correct
The correct answer is A. (20). \(e_s=\frac{e\times100}{RH}=\frac{15\times100}{75}=20\). Exam tip: handle (RH) as a percentage carefully.
Exam Tip
\(e_s=\frac{e\times100}{RH}=\frac{15\times100}{75}=20\) होता है। परीक्षा में (RH) को प्रतिशत से संख्या में बदलकर सोचें।
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