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Chemistry Laws of chemical combination MCQ Questions for Class 11 Science

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01 Practice Topic Nature of matter 584 MCQs 02 Practice Topic Atomic and molecular masses 0 MCQs 03 Practice Topic Mole concept and molar mass 0 MCQs 04 Practice Topic Percentage composition and empirical/molecular formulas 0 MCQs 05 Practice Topic Stoichiometry and calculations 0 MCQs

Laws of chemical combination Practice Questions

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Question 281/531 Easy Chemistry Some Basic Concepts of Chemistry Laws of chemical combination Class 11 Level 18

समान ताप और दाब पर गैसों के आयतन 20 लीटर 30 लीटर और 10 लीटर हैं। सरल अनुपात क्या है?

At the same temperature and pressure gas volumes are 20 litres 30 litres and 10 litres. What is the simplest ratio?

Explanation opens after your attempt
Correct Answer

B. 2:3:1

Step 1

Concept

Dividing all volumes by a common factor gives 2:3:1. Exam tip: simplify gaseous volume ratios.

Step 2

Why this answer is correct

The correct answer is B. 2:3:1. Dividing all volumes by a common factor gives 2:3:1. Exam tip: simplify gaseous volume ratios.

Step 3

Exam Tip

सभी आयतनों को समान कारक से भाग देने पर 2:3:1 मिलता है। परीक्षा में गैसीय आयतन अनुपात सरल करें।

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Question 282/531 Easy Chemistry Some Basic Concepts of Chemistry Laws of chemical combination Class 11 Level 18

समान ताप और दाब पर गैसों के आयतन 9 लीटर 27 लीटर और 18 लीटर हैं। सरल अनुपात क्या है?

At the same temperature and pressure gas volumes are 9 litres 27 litres and 18 litres. What is the simplest ratio?

Explanation opens after your attempt
Correct Answer

C. 1:3:2

Step 1

Concept

Dividing all volumes by a common factor gives 1:3:2. Exam tip: simplify gaseous volume ratios.

Step 2

Why this answer is correct

The correct answer is C. 1:3:2. Dividing all volumes by a common factor gives 1:3:2. Exam tip: simplify gaseous volume ratios.

Step 3

Exam Tip

सभी आयतनों को समान कारक से भाग देने पर 1:3:2 मिलता है। परीक्षा में गैसीय आयतन अनुपात सरल करें।

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Question 283/531 Easy Chemistry Some Basic Concepts of Chemistry Laws of chemical combination Class 11 Level 18

समान ताप और दाब पर गैसों के आयतन 11 लीटर 22 लीटर और 33 लीटर हैं। सरल अनुपात क्या है?

At the same temperature and pressure gas volumes are 11 litres 22 litres and 33 litres. What is the simplest ratio?

Explanation opens after your attempt
Correct Answer

D. 1:2:3

Step 1

Concept

Dividing all volumes by a common factor gives 1:2:3. Exam tip: simplify gaseous volume ratios.

Step 2

Why this answer is correct

The correct answer is D. 1:2:3. Dividing all volumes by a common factor gives 1:2:3. Exam tip: simplify gaseous volume ratios.

Step 3

Exam Tip

सभी आयतनों को समान कारक से भाग देने पर 1:2:3 मिलता है। परीक्षा में गैसीय आयतन अनुपात सरल करें।

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Question 284/531 Easy Chemistry Some Basic Concepts of Chemistry Laws of chemical combination Class 11 Level 18

समान ताप और दाब पर गैसों के आयतन 13 लीटर 26 लीटर और 13 लीटर हैं। सरल अनुपात क्या है?

At the same temperature and pressure gas volumes are 13 litres 26 litres and 13 litres. What is the simplest ratio?

Explanation opens after your attempt
Correct Answer

A. 1:2:1

Step 1

Concept

Dividing all volumes by a common factor gives 1:2:1. Exam tip: simplify gaseous volume ratios.

Step 2

Why this answer is correct

The correct answer is A. 1:2:1. Dividing all volumes by a common factor gives 1:2:1. Exam tip: simplify gaseous volume ratios.

Step 3

Exam Tip

सभी आयतनों को समान कारक से भाग देने पर 1:2:1 मिलता है। परीक्षा में गैसीय आयतन अनुपात सरल करें।

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Question 285/531 Easy Chemistry Some Basic Concepts of Chemistry Laws of chemical combination Class 11 Level 18

समान ताप और दाब पर गैसों के आयतन 15 लीटर 25 लीटर और 5 लीटर हैं। सरल अनुपात क्या है?

At the same temperature and pressure gas volumes are 15 litres 25 litres and 5 litres. What is the simplest ratio?

Explanation opens after your attempt
Correct Answer

B. 3:5:1

Step 1

Concept

Dividing all volumes by a common factor gives 3:5:1. Exam tip: simplify gaseous volume ratios.

Step 2

Why this answer is correct

The correct answer is B. 3:5:1. Dividing all volumes by a common factor gives 3:5:1. Exam tip: simplify gaseous volume ratios.

Step 3

Exam Tip

सभी आयतनों को समान कारक से भाग देने पर 3:5:1 मिलता है। परीक्षा में गैसीय आयतन अनुपात सरल करें।

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Question 286/531 Easy Chemistry Some Basic Concepts of Chemistry Laws of chemical combination Class 11 Level 18

\(NO\) और \(N_2O\) में नाइट्रोजन और ऑक्सीजन के अलग यौगिक दिए हैं। कौन सा नियम लागू होगा?

The pair \(NO\) and \(N_2O\) gives different compounds of nitrogen and oxygen. Which law will apply?

Explanation opens after your attempt
Correct Answer

C. गुणित अनुपात का नियमLaw of multiple proportions

Step 1

Concept

Multiple proportions apply to different compounds of the same two elements. Exam tip: look for same two elements.

Step 2

Why this answer is correct

The correct answer is C. गुणित अनुपात का नियम / Law of multiple proportions. Multiple proportions apply to different compounds of the same two elements. Exam tip: look for same two elements.

Step 3

Exam Tip

एक ही दो तत्वों के अलग यौगिकों पर गुणित अनुपात लागू होता है। परीक्षा में same two elements देखें।

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Question 287/531 Easy Chemistry Some Basic Concepts of Chemistry Laws of chemical combination Class 11 Level 18

\(CuO\) और \(Cu_2O\) में कॉपर और ऑक्सीजन के अलग यौगिक दिए हैं। कौन सा नियम लागू होगा?

The pair \(CuO\) and \(Cu_2O\) gives different compounds of copper and oxygen. Which law will apply?

Explanation opens after your attempt
Correct Answer

D. गुणित अनुपात का नियमLaw of multiple proportions

Step 1

Concept

Multiple proportions apply to different compounds of the same two elements. Exam tip: look for same two elements.

Step 2

Why this answer is correct

The correct answer is D. गुणित अनुपात का नियम / Law of multiple proportions. Multiple proportions apply to different compounds of the same two elements. Exam tip: look for same two elements.

Step 3

Exam Tip

एक ही दो तत्वों के अलग यौगिकों पर गुणित अनुपात लागू होता है। परीक्षा में same two elements देखें।

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Question 288/531 Easy Chemistry Some Basic Concepts of Chemistry Laws of chemical combination Class 11 Level 18

\(SnO\) और \(SnO_2\) में टिन और ऑक्सीजन के अलग यौगिक दिए हैं। कौन सा नियम लागू होगा?

The pair \(SnO\) and \(SnO_2\) gives different compounds of tin and oxygen. Which law will apply?

Explanation opens after your attempt
Correct Answer

A. गुणित अनुपात का नियमLaw of multiple proportions

Step 1

Concept

Multiple proportions apply to different compounds of the same two elements. Exam tip: look for same two elements.

Step 2

Why this answer is correct

The correct answer is A. गुणित अनुपात का नियम / Law of multiple proportions. Multiple proportions apply to different compounds of the same two elements. Exam tip: look for same two elements.

Step 3

Exam Tip

एक ही दो तत्वों के अलग यौगिकों पर गुणित अनुपात लागू होता है। परीक्षा में same two elements देखें।

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Question 289/531 Easy Chemistry Some Basic Concepts of Chemistry Laws of chemical combination Class 11 Level 18

\(FeCl_2\) और \(FeCl_3\) में आयरन और क्लोरीन के अलग यौगिक दिए हैं। कौन सा नियम लागू होगा?

The pair \(FeCl_2\) and \(FeCl_3\) gives different compounds of iron and chlorine. Which law will apply?

Explanation opens after your attempt
Correct Answer

B. गुणित अनुपात का नियमLaw of multiple proportions

Step 1

Concept

Multiple proportions apply to different compounds of the same two elements. Exam tip: look for same two elements.

Step 2

Why this answer is correct

The correct answer is B. गुणित अनुपात का नियम / Law of multiple proportions. Multiple proportions apply to different compounds of the same two elements. Exam tip: look for same two elements.

Step 3

Exam Tip

एक ही दो तत्वों के अलग यौगिकों पर गुणित अनुपात लागू होता है। परीक्षा में same two elements देखें।

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Question 290/531 Easy Chemistry Some Basic Concepts of Chemistry Laws of chemical combination Class 11 Level 18

\(PbO\) और \(PbO_2\) में लेड और ऑक्सीजन के अलग यौगिक दिए हैं। कौन सा नियम लागू होगा?

The pair \(PbO\) and \(PbO_2\) gives different compounds of lead and oxygen. Which law will apply?

Explanation opens after your attempt
Correct Answer

C. गुणित अनुपात का नियमLaw of multiple proportions

Step 1

Concept

Multiple proportions apply to different compounds of the same two elements. Exam tip: look for same two elements.

Step 2

Why this answer is correct

The correct answer is C. गुणित अनुपात का नियम / Law of multiple proportions. Multiple proportions apply to different compounds of the same two elements. Exam tip: look for same two elements.

Step 3

Exam Tip

एक ही दो तत्वों के अलग यौगिकों पर गुणित अनुपात लागू होता है। परीक्षा में same two elements देखें।

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