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In Class 11 Mathematics, under Relations and Functions, students learn how to form the Cartesian product of two sets as the set of all possible ordered pairs (a, b), where a belongs to the first set and b to the second. The topic explains why the order of elements matters, how to represent products using roster form and diagrams, and how to find their number of elements. This foundation helps students describe relations as subsets of a Cartesian product and understand domain and codomain.
Practice questions
01 If A = {1, 2}, B = {3}, and C = {4, 5, 6}, what is n(A × B × C)?
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Answer and explanation
Correct answer: C. 6
Explanation: For three finite sets, the cardinality of their Cartesian product is n(A × B × C) = n(A) × n(B) × n(C). Set A contains 2 elements, set B contains 1 element, and set C contains 3 elements. Therefore, n(A × B × C) = 2 × 1 × 3 = 6. Each ordered triple chooses its first component from A, its second component from B, and its third component from C. The six triples are (1,3,4), (1,3,5), (1,3,6), (2,3,4), (2,3,5), and (2,3,6). Hence option C is correct. Options A and B undercount the independent choices, while option D does not follow the product-of-cardinalities rule.
02 If A = {0, 1} and B = {0, 2}, which pair will not be in A × B?
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Answer and explanation
Correct answer: D. (2, 1)
Explanation: An ordered pair (a, b) belongs to A × B exactly when a ∈ A and b ∈ B. For (0,0), the first 0 is in A and the second 0 is in B, so it is included. For (1,2), 1 ∈ A and 2 ∈ B, so it is included. For (1,0), both membership conditions also hold, so it is included. However, in (2,1), the first component is 2, and 2 is not an element of A; also, the second component 1 is not in B. Therefore (2,1) cannot belong to A × B, making option D correct. The distractors are valid because they respect the required first-set and second-set positions.
03 If (A\subset B), which statement is correct for (C\times A) and (C\times B)?
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Answer and explanation
Correct answer: A. (C\times A\subset C\times B)
Explanation: Elements of (A) in the second component are also in (B), so (C\times A\subset C\times B). With subsets, check the position of the related component.
04 If (A={1}) and (B={2}), what is the difference between (A\times B) and (B\times A)?
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Answer and explanation
Correct answer: A. (A\times B={(1,2)}) and (B\times A={(2,1)})
Explanation: In the first product, (1) is in the first position, and in the second, (2) is in the first position. Order matters even with one element each.
05 If (A={2,4,6}) and (B={1,5}), how many points are obtained when (A\times B) is shown as points?
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Answer and explanation
Correct answer: D. (6)
Explanation: Each ordered pair can be treated like a point, and there are (3\times 2=6) pairs. The same multiplication rule applies in coordinate questions.
06 If shirt color set (A={\text{red},\text{blue}}) and size set (B={\text{small},\text{medium},\text{large}}) are given, how many choices are in (A\times B)?
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Answer and explanation
Correct answer: D. (6)
Explanation: There are (2) colors and (3) sizes, so (2\times 3=6) choices are formed. Real-life combinations are counted using Cartesian product.
08 If (A={1,2,3}) and (B={4,5}), which pairs in (A\times B) have (3) as the first component?
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Answer and explanation
Correct answer: A. ({(3,4),(3,5)})
Explanation: The first component (3) is fixed, and the second component is (4) or (5) from (B). With a fixed first component, only elements of the second set vary.
11 If A = {1, 2} and B = {3, 4, 5}, why is (2, 4) correctly placed in A × B?
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Answer and explanation
Correct answer: A. Because 2 ∈ A and 4 ∈ B
Explanation: The defining condition for membership in a Cartesian product is (a, b) ∈ A × B if and only if a ∈ A and b ∈ B. In the ordered pair (2, 4), the first component is 2. Since 2 is an element of A = {1, 2}, the first condition is satisfied. The second component is 4, and 4 is an element of B = {3, 4, 5}, so the second condition is also satisfied. Therefore (2, 4) belongs to A × B, making option A correct. Option B reverses the required set membership and is false; 2 is not in B and 4 is not in A. Option C is false because 2 and 4 are unequal, and option D is false because A is not empty.
12 If (A={x:x\in \mathbb{N},\ x\leq 2}) and (B={10,20}), how many elements are in (A\times B)?
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Answer and explanation
Correct answer: B. (4)
Explanation: The answer is option B, 4. The set-builder description says A contains natural numbers not greater than 2. Using the usual school convention N={1,2,3,...}, A={1,2}, so n(A)=2. Set B={10,20} has n(B)=2. The Cartesian-product rule gives n(A×B)=n(A)n(B)=2×2=4. Option A counts only one set, while C and D do not follow the multiplication rule. The actual pairs are (1,10),(1,20),(2,10),(2,20), confirming four. If a text defines natural numbers to include 0, A would have three elements, so the convention should be checked; under the supplied school convention, B is correct.
14 If (A={-2,0}) and (B={1}), which is (A\times B)?
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Answer and explanation
Correct answer: A. ({(-2,1),(0,1)})
Explanation: Elements of (A) come in the first position and (1) from (B) comes in the second position. A negative element is used like any ordinary element.
15 If (A={\text{Mon},\text{Tue}}) and (B={\text{morning},\text{evening}}), of which set is ((\text{Mon},\text{evening})) an element?
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Answer and explanation
Correct answer: A. (A\times B)
Explanation: The first component (\text{Mon}) is from (A) and the second component (\text{evening}) is from (B). Therefore, the pair belongs to (A\times B).
16 If (A={1,2}) and (B={3,4}), in which pairs will (4) appear as the second component in (A\times B)?
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Answer and explanation
Correct answer: A. ({(1,4),(2,4)})
Explanation: The second component (4) is fixed and the first component comes from (1) or (2) in (A). With a second-component condition, the first set varies.
17 If (A={3,4}) and (B={5}), which statement is correct?
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Answer and explanation
Correct answer: A. (A\times B={(3,5),(4,5)})
Explanation: A Cartesian product lists ordered pairs. The first member must come from set A, while the second member must come from set B. Since A contains 3 and 4 and B contains only 5, every possible pair has 5 in its second position. Thus the product contains exactly (3,5) and (4,5), with no repeated or unordered entries.
To check the options, pair each element of A with the only element of B: 3 gives (3,5), and 4 gives (4,5). Therefore option A is correct. Option B reverses the order and represents B 5c 7ftimes 7f A, option C is an ordinary collection rather than ordered pairs, and option D is false because neither set is empty.
19 If (A={2,4,6}) and (B={1,2}), how many pairs in (A\times B) have the largest element of (B) as the second component?
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Answer and explanation
Correct answer: B. (3)
Explanation: The largest element of (B) is (2), and the (3) elements of (A) can be first components with it. For a fixed second component, the answer is (n(A)).
21 If (A={1,3}) and (B={2,4}), how many pairs in (A\times B) have an odd sum of components?
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Answer and explanation
Correct answer: C. (4)
Explanation: The direct answer is option C: 4. Set A contains 1 and 3, both odd numbers. Set B contains 2 and 4, both even numbers. An odd number plus an even number is always odd. Therefore every ordered pair in A×B has an odd sum. The complete product is (1,2), (1,4), (3,2), and (3,4), so there are 2×2=4 pairs. Option C is correct. Option A, 0, is wrong because none of the pairs has an even sum; all four sums are odd. Option B, 2, would count only part of the possible pairs and misses two valid pairs. Option D, 6, is impossible because A×B has only 4 pairs in total. The first component must be selected from A and the second from B, giving four combinations. A useful cue is parity: odd plus even always gives odd, so count all product pairs.
22 If (A={2,4}) and (B={1,3}), how many pairs in (A\times B) have an even product of components?
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Answer and explanation
Correct answer: C. (4)
Explanation: The Cartesian product \\(A\\times B\\) contains every ordered pair \\((a,b)\\) with the first component selected from \\(A\\) and the second selected from \\(B\\). Here, \\(A=\\{2,4\\}\\) and \\(B=\\{1,3\\}\\). Both possible first components, 2 and 4, are even. An even number multiplied by any integer is even, so every pair in the Cartesian product has an even product.
There are \\(2\\) choices for the first component and \\(2\\) choices for the second component. By the multiplication principle, the total number of ordered pairs is \\(2\\times2=4\\). They are \\((2,1)\\), \\((2,3)\\), \\((4,1)\\), and \\((4,3)\\), and all products are even. Hence option C is correct.
24 If (A={0,1,2}) and (B={2,3}), how many ordered pairs in (A\times B) have the difference of both components equal to (1)?
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Answer and explanation
Correct answer: B. (2) pairs
Explanation: The pairs are ((1,2)) and ((2,3)), where the difference between the second and first component is (1). In condition-based questions, first list possible pairs and then check.
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